Описание
The "go tool pack" subcommand (usually used only by the compiler as an internal tool with known-good inputs) does not sanitize output filenames. Extracting a malicious archive file with the "pack" subcommand can write files to arbitrary locations on the filesystem.
Пакеты
| Пакет | Статус | Версия исправления | Релиз | Тип |
|---|---|---|---|---|
| golang-1.25 | fixed | 1.25.10-1 | package | |
| golang-1.26 | fixed | 1.26.3-1 | package | |
| golang-1.24 | removed | package | ||
| golang-1.24 | no-dsa | trixie | package | |
| golang-1.19 | removed | package | ||
| golang-1.19 | no-dsa | bookworm | package | |
| golang-1.15 | removed | package | ||
| golang-1.15 | postponed | bullseye | package |
Примечания
https://go-review.googlesource.com/c/go/+/767520
https://github.com/golang/go/issues/78778
https://groups.google.com/g/golang-announce/c/qcCIEXso47M
EPSS
Связанные уязвимости
The "go tool pack" subcommand (usually used only by the compiler as an internal tool with known-good inputs) does not sanitize output filenames. Extracting a malicious archive file with the "pack" subcommand can write files to arbitrary locations on the filesystem.
The "go tool pack" subcommand (usually used only by the compiler as an internal tool with known-good inputs) does not sanitize output filenames. Extracting a malicious archive file with the "pack" subcommand can write files to arbitrary locations on the filesystem.
The "go tool pack" subcommand (usually used only by the compiler as an internal tool with known-good inputs) does not sanitize output filenames. Extracting a malicious archive file with the "pack" subcommand can write files to arbitrary locations on the filesystem.
The "go tool pack" subcommand (usually used only by the compiler as an internal tool with known-good inputs) does not sanitize output filenames. Extracting a malicious archive file with the "pack" subcommand can write files to arbitrary locations on the filesystem.
EPSS