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BDU:2025-12714

Опубликовано: 15 сент. 2025
Источник: fstec
CVSS3: 6.5
CVSS2: 5
EPSS Низкий

Описание

Уязвимость функции dwa_uncompress() компонента OpenEXR File Decoder мультимедийной библиотеки FFmpeg связана с выходом операции за границы буфера в памяти. Эксплуатация уязвимости может позволить нарушителю, действующему удалённо, выполнить произвольный код

Вендор

ООО «Ред Софт»
FFmpeg team

Наименование ПО

РЕД ОС
FFmpeg

Версия ПО

7.3 (РЕД ОС)
до 8.0 (FFmpeg)

Тип ПО

Операционная система
Прикладное ПО информационных систем

Операционные системы и аппаратные платформы

ООО «Ред Софт» РЕД ОС 7.3

Уровень опасности уязвимости

Средний уровень опасности (базовая оценка CVSS 2.0 составляет 5)
Средний уровень опасности (базовая оценка CVSS 3.1 составляет 6,5)
Средний уровень опасности (оценка CVSS 4.0 составляет 5,7)

Возможные меры по устранению уязвимости

Использование рекомендаций производителя:
https://ffmpeg.org/security.html
Для РЕД ОС:
https://redos.red-soft.ru/support/secure/uyazvimosti/mnozhestvennye-uyazvimosti-ffmpeg-10112025/?sphrase_id=1345296

Статус уязвимости

Подтверждена производителем

Наличие эксплойта

Данные уточняются

Информация об устранении

Уязвимость устранена

Идентификаторы других систем описаний уязвимостей

EPSS

Процентиль: 6%
0.00024
Низкий

6.5 Medium

CVSS3

5 Medium

CVSS2

Связанные уязвимости

CVSS3: 7.5
redos
21 день назад

Множественные уязвимости ffmpeg

ubuntu
около 2 месяцев назад

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type (and size), and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decode_header. The buffer td->uncompressed_data is allocated in decode_block based on the xsize, ysize and computed current_channel_offset. The function dwa_uncompress then assumes at [5] that if there are 4 channels, these are "B", "G", "R" and "A", and in the calculations at [6] and [7] that all channels are of the same type, which matches the type of the main color channels. If we set the main color channels to a 4-byte type and add duplicate or unknown channels of the 2-byte EXR_HALF type, then the addition at [7] will increment the pointer by 4-bytes * xsize * nb_channels, which will exceed the allocated buffer. We recommend upgrading to version 8.0 or beyond.

nvd
около 2 месяцев назад

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type (and size), and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decode_header. The buffer td->uncompressed_data is allocated in decode_block based on the xsize, ysize and computed current_channel_offset. The function dwa_uncompress then assumes at [5] that if there are 4 channels, these are "B", "G", "R" and "A", and in the calculations at [6] and [7] that all channels are of the same type, which matches the type of the main color channels. If we set the main color channels to a 4-byte type and add duplicate or unknown channels of the 2-byte EXR_HALF type, then the addition at [7] will increment the pointer by 4-bytes * xsize * nb_channels, which will exceed the allocated buffer. We recommend upgrading to version 8.0 or beyond.

debian
около 2 месяцев назад

When decoding an OpenEXR file that uses DWAA or DWAB compression, ther ...

github
около 2 месяцев назад

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type (and size), and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decode_header. The buffer td->uncompressed_data is allocated in decode_block based on the xsize, ysize and computed current_channel_offset. The function dwa_uncompress then assumes at [5] that if there are 4 channels, these are "B", "G", "R" and "A", and in the calculations at [6] and [7] that all channels are of the same type, which matches the type of the main color channels. If we set the main color channels to a 4-byte type and add duplicate or unknown channels of the 2-byte EXR_HALF type, then the addition at [7] will increment the pointer by 4-bytes * xsize * nb_channels, which will exceed the allocated buffer. We recommend upgrading to version 8.0 or beyond.

EPSS

Процентиль: 6%
0.00024
Низкий

6.5 Medium

CVSS3

5 Medium

CVSS2