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CVE-2017-9502

Опубликовано: 14 июн. 2017
Источник: redhat
CVSS3: 7.8

Описание

In curl before 7.54.1 on Windows and DOS, libcurl's default protocol function, which is the logic that allows an application to set which protocol libcurl should attempt to use when given a URL without a scheme part, had a flaw that could lead to it overwriting a heap based memory buffer with seven bytes. If the default protocol is specified to be FILE or a file: URL lacks two slashes, the given "URL" starts with a drive letter, and libcurl is built for Windows or DOS, then libcurl would copy the path 7 bytes off, so that the end of the given path would write beyond the malloc buffer (7 bytes being the length in bytes of the ascii string "file://").

Затронутые пакеты

ПлатформаПакетСостояниеРекомендацияРелиз
.NET Core 1.0 on Red Hat Enterprise Linuxrh-dotnetcore10-curlNot affected
.NET Core 1.1 on Red Hat Enterprise Linuxrh-dotnetcore11-curlNot affected
.NET Core 2.0 on Red Hat Enterprise Linuxrh-dotnet20-curlNot affected
Red Hat Enterprise Linux 5curlNot affected
Red Hat Enterprise Linux 6curlNot affected
Red Hat Enterprise Linux 7curlNot affected
Red Hat Enterprise Virtualization 3mingw-virt-viewerNot affected
Red Hat JBoss Web Server 3curlNot affected

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Дополнительная информация

Статус:

Moderate
Дефект:
CWE-787
https://bugzilla.redhat.com/show_bug.cgi?id=1461321curl: URL file scheme drive letter buffer overflow

7.8 High

CVSS3

Связанные уязвимости

CVSS3: 5.3
ubuntu
больше 8 лет назад

In curl before 7.54.1 on Windows and DOS, libcurl's default protocol function, which is the logic that allows an application to set which protocol libcurl should attempt to use when given a URL without a scheme part, had a flaw that could lead to it overwriting a heap based memory buffer with seven bytes. If the default protocol is specified to be FILE or a file: URL lacks two slashes, the given "URL" starts with a drive letter, and libcurl is built for Windows or DOS, then libcurl would copy the path 7 bytes off, so that the end of the given path would write beyond the malloc buffer (7 bytes being the length in bytes of the ascii string "file://").

CVSS3: 5.3
nvd
больше 8 лет назад

In curl before 7.54.1 on Windows and DOS, libcurl's default protocol function, which is the logic that allows an application to set which protocol libcurl should attempt to use when given a URL without a scheme part, had a flaw that could lead to it overwriting a heap based memory buffer with seven bytes. If the default protocol is specified to be FILE or a file: URL lacks two slashes, the given "URL" starts with a drive letter, and libcurl is built for Windows or DOS, then libcurl would copy the path 7 bytes off, so that the end of the given path would write beyond the malloc buffer (7 bytes being the length in bytes of the ascii string "file://").

CVSS3: 5.3
debian
больше 8 лет назад

In curl before 7.54.1 on Windows and DOS, libcurl's default protocol f ...

CVSS3: 5.3
github
больше 3 лет назад

In curl before 7.54.1 on Windows and DOS, libcurl's default protocol function, which is the logic that allows an application to set which protocol libcurl should attempt to use when given a URL without a scheme part, had a flaw that could lead to it overwriting a heap based memory buffer with seven bytes. If the default protocol is specified to be FILE or a file: URL lacks two slashes, the given "URL" starts with a drive letter, and libcurl is built for Windows or DOS, then libcurl would copy the path 7 bytes off, so that the end of the given path would write beyond the malloc buffer (7 bytes being the length in bytes of the ascii string "file://").

7.8 High

CVSS3