Описание
Уязвимость компонента x86/mm ядра операционной системы Linux связана с непроверенным возвращаемым значением. Эксплуатация уязвимости может позволить нарушителю вызвать отказ в обслуживании
Вендор
Наименование ПО
Версия ПО
Тип ПО
Операционные системы и аппаратные платформы
Уровень опасности уязвимости
Возможные меры по устранению уязвимости
Статус уязвимости
Наличие эксплойта
Информация об устранении
Ссылки на источники
Идентификаторы других систем описаний уязвимостей
- CVE
EPSS
5.5 Medium
CVSS3
4.6 Medium
CVSS2
Связанные уязвимости
In the Linux kernel, the following vulnerability has been resolved: x86/mm: Check return value from memblock_phys_alloc_range() At least with CONFIG_PHYSICAL_START=0x100000, if there is < 4 MiB of contiguous free memory available at this point, the kernel will crash and burn because memblock_phys_alloc_range() returns 0 on failure, which leads memblock_phys_free() to throw the first 4 MiB of physical memory to the wolves. At a minimum it should fail gracefully with a meaningful diagnostic, but in fact everything seems to work fine without the weird reserve allocation.
In the Linux kernel, the following vulnerability has been resolved: x86/mm: Check return value from memblock_phys_alloc_range() At least with CONFIG_PHYSICAL_START=0x100000, if there is < 4 MiB of contiguous free memory available at this point, the kernel will crash and burn because memblock_phys_alloc_range() returns 0 on failure, which leads memblock_phys_free() to throw the first 4 MiB of physical memory to the wolves. At a minimum it should fail gracefully with a meaningful diagnostic, but in fact everything seems to work fine without the weird reserve allocation.
In the Linux kernel, the following vulnerability has been resolved: x86/mm: Check return value from memblock_phys_alloc_range() At least with CONFIG_PHYSICAL_START=0x100000, if there is < 4 MiB of contiguous free memory available at this point, the kernel will crash and burn because memblock_phys_alloc_range() returns 0 on failure, which leads memblock_phys_free() to throw the first 4 MiB of physical memory to the wolves. At a minimum it should fail gracefully with a meaningful diagnostic, but in fact everything seems to work fine without the weird reserve allocation.
x86/mm: Check return value from memblock_phys_alloc_range()
In the Linux kernel, the following vulnerability has been resolved: x ...
EPSS
5.5 Medium
CVSS3
4.6 Medium
CVSS2